Show the homolysis reaction of benzoyl peroxide,$(C_6H_5CO)_2O_2$.
The homolysis of benzoyl peroxide $(C_6H_5CO)_2O_2$ involves the cleavage of the $O-O$ bond to form two benzoyloxy radicals,which subsequently undergo decarboxylation to form phenyl radicals and carbon dioxide:
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
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Similar Questions
The decreasing order of stability of the following carbocations is:
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$
Medium
View SolutionIn the potential energy diagram shown,the point $X$ represents:
Easy
View SolutionArrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:
DifficultJEE MAIN 2026
View SolutionThe correct order of stability of the carbocations given below is:
Medium
View SolutionThe order of circled $C-H$ bond dissociation energy in the following compounds is:
DifficultTS EAMCET 2020
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